Question: Using the axioms of probability, show that P(AUBUC)= P(A)+P(B) +P(C)- P(ANB) - P(AnC) -P(BnC)+P(ANBNC).

Using the axioms of probability, show that
P(AUBUC)= P(A)+P(B) +P(C)- P(ANB) - P(AnC) -P(BnC)+P(ANBNC).

P(AUBUC)= P(A)+P(B) +P(C)- P(ANB) - P(AnC) -P(BnC)+P(ANBNC).

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