Water is flowing in a trapezoidal channel at a rate of Q = 20 m 3 /s. The critical depth
Water is flowing in a trapezoidal channel at a rate of Q = 20 m3/s. The critical depth y for such channel must satisfy the equation 0 = 1 – Q2/gA3c B. Where g = 9.81 m/s2, Ac = the cross-sectional area (m2), and B = the width of the channel at the surface (m). For this case, the width and the cross- sectional area can be related to depth y by
B = 3 + y and Ac 3y + y2/2
Solve for the critical depth using
(a) The graphical method,
(b) Bisection, and
(c) False position. For (b) and (c) use initial guesses of xt = 0.5 xa = 2.5, and iterate until the approximate error falls below 1 % or the number of iterations exceeds 10. Discuss your results.
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