Question: we define the first difference δf of a function f (x) by δf (x) = f (x + 1) f (x). 41. First show that

we define the first difference δf of a function f (x) by δf (x) = f (x + 1) ˆ’ f (x).
41. First show that
We define the first difference δf of a function f

satisfies δP = (x + 1). Then apply Exercise 40 to conclude that

We define the first difference δf of a function f

x(x+1) P(x)= n(n 1) 1+2+3++

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41 Let Px xx 12 Then Px Px 1 Px Also note that P0 0 Thus by Exercise 40 with k 1 it follows that 43 ... View full answer

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