Question: When a certain resistor is connected to an ac generator with a maximum voltage of 15 V, the average power dissipated in the resistor is

When a certain resistor is connected to an ac generator with a maximum voltage of 15 V, the average power dissipated in the resistor is 22 W.

(a) What is the resistance of the resistor?

(b) What is the rms current in the circuit?

(c) We know that Pav = I2rmsR, and hence it seems that reducing the resistance should reduce the average power. On the other hand, we also know that Pav = V2rms/R, which suggests that reducing R increases Pav. Which conclusion is correct? Explain.

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