Question: When is unknown and the sample is of size n 30, there are two methods for computing confidence intervals for . Method 1:
Method 1: Use the Student’s t distribution with d.f. = n – 1.
This is the method used in the text. It is widely employed in statistical studies. Also, most statistical software packages use this method.
Method 2: When n ≥ 30, use the sample standard deviation s as an estimate for σ, and then use the standard normal distribution.
This method is based on the fact that for large samples, s is a fairly good approximation for σ. Also, for large n, the critical values for the Student’s t distribution approach those of the standard normal distribution.
Consider a random sample of size n = 31, with sample mean = 45.2 and sample standard deviation s = 5.3.
(a) Compute 90%, 95%, and 99% confidence intervals for μ using Method 1 with a Student’s t distribution. Round endpoints to two digits after the decimal.
(b) Compute 90%, 95%, and 99% confidence intervals for μ using Method 2 with the standard normal distribution. Use s as an estimate for s. Round endpoints to two digits after the decimal.
(c) Compare intervals for the two methods. Would you say that confidence intervals using a Student’s t distribution are more conservative in the sense that they tend to be longer than intervals based on the standard normal distribution?
(d) Repeat parts (a)–(c) for a sample of size n = 81. With increased sample size, do the two methods give confidence intervals that are more similar?
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a b c Yes the respective intervals based on the students t distribution are slightly longer d Th... View full answer
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