When phenyl isothiocyanate, C6H5N C S, is reduced with lithium aluminum hydride, the product formed has these spectral data MS (m z) 107, 106 IR (cm 1) 3330 (sharp), 3050, 2815, 760, 700 1H NMR () 2 7 (s, 3H), 3 5 (broad, 1H), 6 6 (d, 2H), 6 7 (t, 1H) 7 2 (t, 2H) 13C NMR () 30 (CH3), 112 (CH), 117 (CH), 129 (CH), 150 (C) (a) What is the structure of the product (b) What is the structure that accounts for the 106 m z peak and how is it formed (It is an iminium ion )

Question: When phenyl isothiocyanate, C6H5N == C == S, is reduced with lithium aluminum hydride, the product formed has these spectral data: MS (m/z): 107, 106

When phenyl isothiocyanate, C6H5N == C == S, is reduced with lithium aluminum hydride, the product formed has these spectral data:
MS (m/z): 107, 106
IR (cm-1): 3330 (sharp), 3050, 2815, 760, 700
1H NMR (δ): 2.7 (s, 3H), 3.5 (broad, 1H), 6.6 (d, 2H), 6.7 (t, 1H) 7.2 (t, 2H)
13C NMR (δ): 30 (CH3), 112 (CH), 117 (CH), 129 (CH), 150 (C)
(a) What is the structure of the product?
(b) What is the structure that accounts for the 106 m/z peak and how is it formed? (It is an iminium ion.)

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