1. In a hydraulic system a 20.0-N force is applied to the small piston with cross-sectional area...
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2. If the diameter of the larger piston in Problem 1 is doubled, how is the weight able to be lifted changed?
3. If a dentist’s chair weighs 1600 N and is raised by a large piston with cross-sectional area of 75.0 cm2, what force must be exerted on a small piston of cross-sectional area 3.75 cm2 to lift the chair?
4. A hydraulic jack whose piston has a cross-sectional area of 115 cm2 supports a pickup truck weighing 1.20 x 104 N. Compressed air is used to apply a force on the second piston with cross-sectional area 25.0 cm2. How large must this force be to support the truck?
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1 F 2 F 1 A 2 A 1 200 N 500 cm 2 250 cm 2 400 N 2 Since the a...View the full answer
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Related Book For 
Applied Physics
ISBN: 978-0132109277
10th Edition
Authors: Dale ewen, Neill schurter, P. erik gundersen
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