A 0.150 kg particle moves along an x axis according to x(t) = 13.00 + 2.00t
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A 0.150 kg particle moves along an x axis according to x(t) = – 13.00 + 2.00t + 4.00t2 – 3.00t3, with x in meters and t in seconds. In unit-vector notation, what is the net force acting on the particle at t = 3.40 s?
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Related Book For
Fundamentals of Physics
ISBN: 978-0471758013
8th Extended edition
Authors: Jearl Walker, Halliday Resnick
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