A 100.0 mL solution of 0.0500 M Mn buffered to pH 9.00 was titrated with 0.0500 M
Question:
(a) What is the equivalence volume, Ve, in milliliters?
(b) Calculate the concentration of Mn+ at V = 1/2 Ve+.
(c) What fraction (α γ4-) of free EDTA is in the form γ 4- at pH 9.00?
(d) The formation constant (Kf) is (10)12.00. Calculate the value of the conditional formation constant Kf'(= α γ4-Kf)
(e) Calculate the concentration of Mn+ at V = Ve+.
(f) What is the concentration of Mn+ at V = 1.100 Ve?
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a b c d e f mmol EDTA mmol Mr Ve 00500M 1000 mL 0500 M Ve 1000 mL Mn fraction ...View the full answer
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