A 1.5-MeV (kinetic energy) proton enters a 0.30-T field, in a plane perpendicular to the field. What
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A 1.5-MeV (kinetic energy) proton enters a 0.30-T field, in a plane perpendicular to the field. What is the radius of its path?
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The kinetic energy of the proton can be used to find i...View the full answer
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