Question: A 50-kg block is placed on an inclined plane whose angle with the horizontal is 25. The viscous friction coefficient between the block and the

A 50-kg block is placed on an inclined plane whose angle with the horizontal is 25°. The viscous friction coefficient between the block and the plane is c = 6 N s/m.
(a) Derive the equation of motion,
(b) Solve the equation of motion for the speed v(t) of the block, assuming that the block is initially given a speed of 5 m/s.
(c) Find the steady-state speed of the block and estimate the time required to reach that speed,
(d) Discuss the effect of the initial velocity of the steady-state speed.

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a Summing forces parallel to the plane we obtain b vt 2943 2543et... View full answer

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