Question: A ball with radius R and I = (2/5)mR2 rolls with speed V0 without slipping on the ground. It encounters a step of height h
A ball with radius R and I = (2/5)mR2 rolls with speed V0 without slipping on the ground. It encounters a step of height h and rolls up over it. Assume that the ball sticks to the corner of the step briefly (until the center of the ball is directly above the corner). Show that if the ball is to climb over the step, then V0 mustsatisfy
10gh (1 5h (7.60) Vo 2 7R
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We will use the fact that the angular momentum of the ball with respect to the corner of the step ... View full answer
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