Question: A battery with e = 12.0 V and internal resistance is connected to two 7.5-k resistors in series. An ammeter of internal resistance 0.50

A battery with e = 12.0 V and internal resistance is connected to two 7.5-kΩ resistors in series. An ammeter of internal resistance 0.50 Ω measures the current, and at the same time a voltmeter with internal resistance 15 kΩ measures the voltage across one of the 7.5-kΩ resistors in the circuit. What do the ammeter and voltmeter read? What is the %"error" from the current and voltage without meters?

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