A carboxylic acid is formed when an α haloketone reacts with hydroxide ion. This reaction is called a Favorskii reaction. Propose a mechanism for the following Favorskii reaction. (Hint: In the first step, HO- removes a proton from the α - carbon that is not bonded to Br; a three-membered ring is formed in the second step; and HO- is a nucleophile in the third step.)

Transcribed Image Text:

CH3CHICCH-CH3 CH3CH.CHCƠ H,O H20 CH