(a) For the circuit show in Fig. 18.10, traverse loop 3 opposite to the direction shown, and...
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(b) Repeat the procedure in part (a) by traversing loops 1 and 2 in the direction opposite that taken in the text, and demonstrate that equations equivalent to those in Example 18.5 are obtained.
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Loop 2 12V 2.0 Ω Loop 1 6.0 Ω V 6.0 V Loop 3
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a Around loop 3 V 1 I 1 R 1 I 2 R 2 0 or V 1 I 1 R 1 I 2 R 2 0 which is the result of the ...View the full answer
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