Question: A golfer tees off from the top of a rise, giving the golf ball an initial velocity of 43 m/s at an angle of 30
A golfer tees off from the top of a rise, giving the golf ball an initial velocity of 43 m/s at an angle of 30° above the horizontal. The ball strikes the fairway a horizontal distance of 180 m from the tee. Assume the fairway is level.
(a) How high is the rise above the fairway?
(b) What is the speed of the ball as it strikes the fairway?
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We make use of Eq 424 and Eq 425 a With x 180 m 0o 30 and vo 43 ms we obtain ytan30 ... View full answer

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