Question: A moderate wind accelerates a pebble over a horizontal xy plane with a constant acceleration a = (5.00 m/s 2 )i + (7.00m/s 2 )j.
A moderate wind accelerates a pebble over a horizontal xy plane with a constant acceleration a = (5.00 m/s2)i + (7.00m/s2)j. At time t = 0, the velocity is (4.00m/s)i. What are the
(a) Magnitude and
(b) Angle of its velocity when it has been displaced by 12.0 m parallel to the x axis?
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a Vo X Vost aj We find t by solving Ax xo 1200400500 where Ax 120 m v 400 ms and ax 50... View full answer
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