A parallel-plate capacitor has a capacitance C0 and a plate separation d. Two dielectric slabs of constants ?1 and ?2, each of thickness d

A parallel-plate capacitor has a capacitance C0 and a plate separation d. Two dielectric slabs of constants ?1 and ?2, each of thickness ½ d and having the same area as the plates, are inserted between the plates as shown in Figure. When the charge on the plates is Q, find

(a) The electric field in each dielectric and

(b) The potential difference between the plates.

(c) Show that the new capacitance is given by C = 2?1 ?2/( ?1 + ?2)C0.

(d) Show that this system can be considered to be a series combination of two capacitors of thickness ½ d filled with dielectrics of constant ?1 and ?2.

i d/2 d/2 K2