A parallel-plate capacitor has a plate area A and a separation d. A metal slab of thickness

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A parallel-plate capacitor has a plate area A and a separation d. A metal slab of thickness t and area A is inserted between the plates.

(a) Show that the capacitance is given by C = є0A/(d - t), regardless of where the metal slab is placed.

(b) Show that this arrangement can be considered to be a capacitor of separation a in series with one of separation b, where a + b + t = d.

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