A particle moves in the xy plane with constant acceleration At t 0 the particle is at r 1 4 m i 3 m j, with velocity v 1 At t 2 s the particle has moved to r 2 10 m i 2 m j, and its velocity has changed to v 2 (5 i 6 j) m s (a) Find v 1 (b) What is the acceleration of the particle (c) What is the velocity of the particle as a function of time (d) What is the position vector of the particle as a function of time

Question: A particle moves in the xy plane with constant acceleration. At t = 0 the particle is at r 1 = 4 m i +

A particle moves in the xy plane with constant acceleration. At t = 0 the particle is at r₁ = 4 m i + 3 m j, with velocity v₁. At t = 2 s the particle has moved to r₂ = 10 m i - 2 m j, and its velocity has changed to v₂ = (5 i - 6 j) m/s.

(a) Find v₁.

(b) What is the acceleration of the particle?

(d) What is the position vector of the particle as a function of time?

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