A particle of charge q and mass m has momentum p = mv and kinetic energy K

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A particle of charge q and mass m has momentum p = mv and kinetic energy K = ½mv 2 = p2/2m. If the particle moves in a circular orbit of radius r perpendicular to a uniform magnetic field B, show that

(a) p = Bqr and

(b) K = B2q2r2/2m.

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Fundamentals of Ethics for Scientists and Engineers

ISBN: 978-0195134889

1st Edition

Authors: Edmund G. Seebauer, Robert L. Barry

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Question Posted: Jul 27, 2011 10:37 AM

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A particle of charge q and mass m has momentum p = mv and kinetic energy K

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Fundamentals of Ethics for Scientists and Engineers

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