A resistor and a capacitor are connected in parallel across a sinusoidal emf = E max
Question:
A resistor and a capacitor are connected in parallel across a sinusoidal emf ← = Emax cos ωt as shown in Figure.
(a) Show that the current in the resistor is IR = (←max/R) cos ωt.
(b) Show that the current in the capacitor branch is IC = (←max/XC) cos (ωt + 90°).
(c) Show that the total current is given by I = IR + IC = Imax cos (ωt + δ), where tan δ = R/XC and Imax = ←max/Z with Z–2 = R–2 + XC–2.
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a From Ohms law I R t V t R Here V t t max cos t so I R t max R cos t b ...View the full answer
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Related Book For 
Fundamentals of Ethics for Scientists and Engineers
ISBN: 978-0195134889
1st Edition
Authors: Edmund G. Seebauer, Robert L. Barry
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