Question: A rod of length |E| is perpendicular to a long wire carrying current I, as shown in Figure. The near end of the rod is

A rod of length |E| is perpendicular to a long wire carrying current I, as shown in Figure. The near end of the rod is a distance d away from the wire. The rod moves with a speed v in the direction of the current I.

(a) Show that the potential difference between the ends of the rod is given by

(b) Use Faraday's law to obtain this result by considering the flux through a rectangula r area A = ? vt swept out by the rod.

V =C0" v h In

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