Question: (a) Show that = A sin kx, where k is a constant, is not a solution of Eq. (40.1) for U = U0 and E
(a) Show that ψ = A sin kx, where k is a constant, is not a solution of Eq. (40.1) for U = U0 and E < U0. 9
(b) Is this ψ a solution for E > U0?
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a Eq401 dy 2m dx Lefthand side But k 2m Uw Ey d 2m ... View full answer
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