Question: (a) Show that a small change dn in the index of refraction of a lens material produces a small change in the focal length df

(a) Show that a small change dn in the index of refraction of a lens material produces a small change in the focal length df given approximately by df/f = –dn/(n – 1).

(b) Use this result to find the focal length of a thin lens for blue light, for which n = 1.53, if the focal length for red light, for which n = 1.47, is 20 cm.

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