A slower-moving car is traveling behind a faster-moving bus. The velocities of the two vehicles are as
Question:
A slower-moving car is traveling behind a faster-moving bus. The velocities of the two vehicles are as follows:
AG = velocity of the Car relative to the Ground = +12 m/s
BG = velocity of the Bus relative to the Ground = +16 m/s
A passenger on the bus gets up and walks toward the front of the bus with a velocity of the bus with a velocity of 
PB, where 
PC, the velocity of the Passenger relative to the Car?
(a) +12 m/s + 16 m/s + 12 m/s = + 130 m/s
(b) -2 m/s + 16 m/s + 12 m/s = +26 m/s
(c) +2 m/s + 16 m/s - 12 m/s = +6 m/s
(d) -2 m/s + 16 m/s 2 12 m/s = +2 m/s
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c The velocity v PC of the passenger relative to the car ...View the full answer
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