A solution containing 3.47 mM X (analyte) and 1.72 mM S (standard) gave peak areas of 3

Question:

A solution containing 3.47 mM X (analyte) and 1.72 mM S (standard) gave peak areas of 3 473 and 10 222, respectively, in a chromatographic analysis. Then 1.00 mL of 8.47 mM S was added to 5.00 mL of unknown X, and the mixture was diluted to 10.0 mL. This solution gave peak areas of 5 428 and 4 431 for X and S, respectively.
(a) Calculate the response factor for the analyte.
(b) Find the concentration of S (mM) in the 10.0 mL of mixed solution.
(c) Find the concentration of X (mM) in the 10.0 mL of mixed solution.
(d) Find the concentration of X in the original unknown.