A water sample is found to have 0.016% deuterium content (that is, 0.016% of the hydrogen nuclei in the water are 2H). If the fusion reaction (2H + 2H) yields 3.65 MeV of energy on average, how much energy could you get from 1.00 L of the water? (There are two reactions with approximately equal probabilities; one yields 4.03 MeV and the other 3.27 MeV.) Assume that you are able to extract and fuse 87.0% of the deuterium in the water. Give your answer in kilowatt hours.