Question: (a) Write down the exact solution to the initial value problem du/dt = 2/7u, u(0) = 1/3. (b) Suppose you make the approximation u(0) =
(b) Suppose you make the approximation u(0) = .3333. At what point does your solution differ from the true solution by 1 unit? by 1000?
(c) Answer the same question if you also approximate the coefficient in the differential equation by
du/dt = .2857 u.
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a ut 13 e 2t7 b One unit t log113 3333 27 360813 1000 units t log100... View full answer
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