Question: [(AB) ]f = (AB)(Cf) = A[B(Cf)], = where (3.3) was used twice; first with A and B in (3.3) replaced by AB and C, respectively,

[(AB) ]f = (AB)(Cf) = A[B(Cf)], = where (3.3) was used twice; first with A and B in (3.3) replaced by AB and C, respectively, and then with f in (3.3) replaced with the function Cf . Also, [A(BC)] f = A[(BC) f ] = A[B(Cf)], which equals [(AB)C]f .

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