Alex says, &8220; The formula for the root mean square error is long. Why do you have to square and then take the square root? Isn't that just doing a lot of work for nothing? Can't you just make them all positive, add them up, and divide?" Help Calista show Alex that his method does not give the same value as the root mean square error.
Use the residual set -2, 1, -3, 4, -1 in your demonstration. Do you think Alex's method could be used as another measure of accuracy? Explain your reasoning.