Question: An electric field given by E = 4.0i 3.0(y2 + 2.0)j pierces a Gaussian cube of edge length 2.0 m and positioned as shown

An electric field given by E = 4.0i – 3.0(y2 + 2.0)j pierces a Gaussian cube of edge length 2.0 m and positioned as shown in Figure (The magnitude E is in Newton’s per coulomb and the position x is in meters.) What is the electric flux through the

(a) Top face,

(b) Bottom face,

(c) Left face, and

(d) Back face?

(e) What is the net electric flux through the cube?

Step by Step Solution

3.32 Rating (167 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

We use J dA and note that the side length of the cube is 30 m10 m 20 m a On the t... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Document Format (1 attachment)

Word file Icon

2-P-E-G-L (162).docx

120 KBs Word File

Students Have Also Explored These Related Electricity and Magnetism Questions!