Question: An electric field given by E = 4.0i 3.0(y2 + 2.0)j pierces a Gaussian cube of edge length 2.0 m and positioned as shown
An electric field given by E = 4.0i – 3.0(y2 + 2.0)j pierces a Gaussian cube of edge length 2.0 m and positioned as shown in Figure (The magnitude E is in Newton’s per coulomb and the position x is in meters.) What is the electric flux through the
(a) Top face,
(b) Bottom face,
(c) Left face, and
(d) Back face?
(e) What is the net electric flux through the cube?
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