Question: An electron is in the ground state in a three-dimensional box, with V given by (3.60), with a = 1.00 nm, b = 2.00 nm,
(a) 0 ≤ x ≤ 0.40 nm, 1.50 nm ≤ y ≤ 2.00 nm, 2.00 nm ≤ z ≤ 3.00 nm;
(b) 0 ≤ x ≤ 0.40 nm, 0 ≤ y ≤ 2.00 nm, 0 ≤ z ≤ 5.00 nm.
(c) What is the probability that a measurement of this electron's position will find it with its x coordinate between 0 and 0.40 nm?
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a Use of Eqs 374 and A2 gives 03065 009085 03871 00108 b The y and z rang... View full answer
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