Question: An object throw directly upward is at a height of s = - 16t2 + 48t + 256 feel after t seconds (see Example 4).

An object throw directly upward is at a height of s = - 16t2 + 48t + 256 feel after t seconds (see Example 4).
(a) What is its initial velocity?
(b) When does it reach its maximum height?
(c) What is its maximum height?
(d) When does it hit the ground?
(e) With what speed does it hit the ground?

Step by Step Solution

3.44 Rating (163 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

a vt 32t 48 initial velocity v 0 48 ftsec b 32... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Document Format (1 attachment)

Word file Icon

955-M-C-D-E (1684).docx

120 KBs Word File

Students Have Also Explored These Related Calculus Questions!