Question: An object thrown directly upward from ground level with an initial velocity of 48 feet per second is s = 48t - 16t2 feet high

An object thrown directly upward from ground level with an initial velocity of 48 feet per second is s = 48t - 16t2 feet high at the end of t seconds.
(a) What is the maximum height attained?
(b) How fast is the object moving, and in which direction, at the end of 1 second?
(c) How long does it take to return to its original position?

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