Question: Angular Width of a Principal Maximum consider N evenly spaced narrow slits. Use the small-angle approximation sin = (for in radians) to prove the following:

Angular Width of a Principal Maximum consider N evenly spaced narrow slits. Use the small-angle approximation sin θ = θ (for θ in radians) to prove the following: For an intensity maximum that occurs at an angle θ, the intensity minima immediately adjacent to Ibis maximum are at angles θ + λ/Nd and o - A/Nd, so that the angular width of the principal maximum is 2λ/Nd. This is proportional to l/N, as we concluded in Section 36.4 on the basis of energy conservation.

Step by Step Solution

3.31 Rating (181 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

IDENTIFY and SET UP Relate the phase difference between adjacent slits to the sum ... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Document Format (1 attachment)

Word file Icon

P-L-O-D-P (176).docx

120 KBs Word File

Students Have Also Explored These Related Light and Optics Questions!