Apply Eqs. 7.7 and 7.10 directly to Eqs. 7.1 and 7.2 and derive the relations of Eqs.

Question:

Apply Eqs. 7.7 and 7.10 directly to Eqs. 7.1 and 7.2 and derive the relations of Eqs. 7.11 and 7.12.
Eq. 7.1
du = Tds - Pdv
Eq. 7.2
dh = Tds + vdP
Eq. 7.7
dz = (∂z/∂x)y dx + (∂z/∂y)x dy
Eq. 7.11
(∂T/∂v)s = - (∂P/∂s)v
Eq. 7.12
(∂T/∂P)s = (∂v/∂s)P
Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question

Thermodynamics for Engineers

ISBN: ?978-1133112860

1st edition

Authors: Kenneth A. Kroos, Merle C. Potter

Question Posted: