Question: At one time, a common means of forming small quantities of oxygen gas in the laboratory was to heat KClO3: For this reaction, calculate ÎH

At one time, a common means of forming small quantities of oxygen gas in the laboratory was to heat KClO3:

For this reaction, calculate Î”H for the formation of
(a) 1.36 mol of O2
(b) 10.4 g of KCl.
(c) The decomposition of KClO3 proceeds spontaneously when it is heated. Do you think that the reverse reaction, the formation of KClO3 from KCl and O2, is likely to be feasible under ordinary conditions? Explain your answer.

2 KCOg(s)- 2 KCI(s) + 302(g) H-_89.4 kl

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a 136 mol O 2 894 kJ 3 mol O 2 4053 405 kJ b 104 g KCI 1 mol KCI 7455 g KCI 894 kJ2 mol KCI 6... View full answer

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