Question: Boron trifluoride, BF3, and diethyl ether, (C2H5)2O, react to produce a compound with the formula BF3 (C2H5)2O. A coordinate covalent bond is formed between

Boron trifluoride, BF3, and diethyl ether, (C2H5)2O, react to produce a compound with the formula BF3 ∙ (C2H5)2O. A coordinate covalent bond is formed between the boron atom on BF3 and the oxygen atom on (C2H5)2O. Write the equation for this reaction, using Lewis electron-dot formulas. Label the Lewis acid and the Lewis base. Determine how many grams of BF3 ∙ (C2H5)2O are formed when 10.0 g BF3 and 20.0 g (C2H5)2O are placed in a reaction vessel, assuming that the reaction goes to completion.

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