Question: Bromination of 3-methyl-2-butanone yielded two compounds, each having the molecular formula C5H9BrO, in a 95:5 ratio. The 1H NMR spectrum of the major isomer A
Bromination of 3-methyl-2-butanone yielded two compounds, each having the molecular formula C5H9BrO, in a 95:5 ratio. The 1H NMR spectrum of the major isomer A was characterized by a doublet at δ 1.2 ppm (6 protons), a septet at δ 3.0 ppm (1 proton), and a singlet at δ 4.1 ppm (2 protons). The 1H NMR spectrum of the minor isomer B exhibited two singlets, one at δ 1.9 ppm and the other at δ 2.5 ppm. The lower field singlet had half the area of the higher field one. Suggest reasonable structures for these two compounds.
Step by Step Solution
3.46 Rating (156 Votes )
There are 3 Steps involved in it
Bromination can occur at either of the two acarbon atoms CHCCHCH32 3Methyl2butanone CH BrCHCCCH3 84... View full answer
Get step-by-step solutions from verified subject matter experts
Document Format (1 attachment)
C-O-EE (39).docx
120 KBs Word File
