Question: By factoring z4 4z2 + 3 into two quadratic factors and using inequality (8), Sec. 4, show that if z lies on the circle |z|

By factoring z4 ˆ’ 4z2 + 3 into two quadratic factors and using inequality (8), Sec. 4, show that if z lies on the circle |z| = 2, then
z4 - 422 + 3 3 VI

z4 - 422 + 3 3 VI

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