Calculate the molarity of each of the following solutions: (a) 6.57 g of methanol (CH3OH) in 1.50
Question:
(a) 6.57 g of methanol (CH3OH) in 1.50 x 102 mL of solution,
(b) 10.4 g of calcium chloride (CaCl2) in 2.20 x 102 mL of solution,
(c) 7.82 g of naphthalene (C10H8) in 85.2 mL of benzene solution.
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a b c mol CH3OH 657...View the full answer
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