Question: Consider a region of space divided by a plane. The potential energy of a particle in region 1 is U1 and in region 2 it
Consider a region of space divided by a plane. The potential energy of a particle in region 1 is U1 and in region 2 it is U2. If a particle of mass m and with speed v1 in region 1 passes from region 1 to region 2 such that its path in region 1 makes an angle θ1 with the normal to the plane of separation and an angle θ2 with normal when in region 2, show that where T1 = ½ mv2/1. What is the optical analog of this problem?
sin e U, - U1/2 sin 02
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U U Let us choose the xy coordinates so that the two regions are divided by the y axis U x 0 u... View full answer
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