Consider the curve r(t) = 2r i + t2j + (1 - t2)k a. Show that this
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a. Show that this curve lies on a plane and find the equation of this plane.
b. Where does the tangent live at t = 2 intersect the xy-plane?
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a rt 2t i t 2 j 1 t 2 k Notice that xt yt zt 2t t 2 1 t 2 2t 1 Since x 2t we have x y ...View the full answer
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