Consider the following LP Maximize z 2x1 4x2 4x3 3x4 Subject to X1 x2 x3 4 X1 4x2 x4 8 X1, x2, x3, x4 yen 0 Using x3 and x4 as starting variables, the optimal tableau is given as Basic Solution 26 25 r2 2 5

Question: Consider the following LP: Maximize z = 2x1 + 4x2 + 4x3 - 3x4 Subject to X1 + x2 + x3 = 4 X1 +

Consider the following LP:
Maximize z = 2x1 + 4x2 + 4x3 - 3x4
Subject to
X1 + x2 + x3 = 4
X1 + 4x2 + x4 = 8
X1, x2, x3, x4 ‰¥ 0
Using x3 and x4 as starting variables, the optimal tableau is given as

Basic Solution 26 -.25 r2 -2.5

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