Consider the following LP: Maximize z = 2x1 + 4x2 + 4x3 - 3x4 Subject to X1
Question:
Maximize z = 2x1 + 4x2 + 4x3 - 3x4
Subject to
X1 + x2 + x3 = 4
X1 + 4x2 + x4 = 8
X1, x2, x3, x4 ¥ 0
Using x3 and x4 as starting variables, the optimal tableau is given as
Transcribed Image Text:
Basic Solution 26 -.25 r2 -2.5
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