Consider the following LP: Maximize z = 4x1 + x2 Subject to 3x1 + x2 = 3
Question:
Consider the following LP:
Maximize z = 4x1 + x2
Subject to
3x1 + x2 = 3
4x1 + 3x2 ≥ 6
X1 + 2x2 ≤ 4
X1, x2 ≥ 0
The starting solution consists of artificial x4 and x5 for the first and second constrains and slack x6 for the third constraint. Using M = 100 for the artificial variables, the optimal tableau is given as
Writer the associated dual problem and determine its optimal solution in two ways.
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Dual Maximize w 3y 1 6y 2 4y 3 St 3y 1 4y 2 y 3 4 y 1 3y 2 2y 3 1 y 2 0 ...View the full answer
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Sinmon Warui Kamau
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