Consider the function e(h) = /h+ h2/6 M, Where M is a bound for the third derivative
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e(h) = ε/h+ h2/6 M,
Where M is a bound for the third derivative of a function Show that e(h) has a minimum at 3√(3ε/M).
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Since eh h 2 hM 3 we have e h ...View the full answer
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