Deduce the structure of each of the following compounds on the basis of their 1H NMR spectra
Question:
(a) C8H10; 1.2 ppm (triplet, 3H)
δ2.6 ppm (quartet, 2H)
δ 7.1 ppm (broad singlet, 5H)
(b) C10H14; δ 1.3 ppm (singlet, 9H)
δ 7.0 to 7.5 ppm (multiplet, 5H)
Transcribed Image Text:
(c) C,H14, δ 0.8 ppm (double. I 2H) 8 1.4 ppm (heptet, 2H) δ 0.9 ppm (triplet, 3H) 81.6 ppm (singlet, 3H) 81.7 ppm (singlet, 3H) δ 2.0 ppm (pentel, 2H) δ 5.1 ppm (triplet, IH) δ 2.2 ppm (singlet, 3H) δ 4.1 ppm (doublet, 2H) δ 5.7 ppm (triplet, IH) (g) C,H,C10: δ 2.0 ppm (pente, 2H) δ 2.8 ppm (singlet, 1H) 83.7 ppm (triplet, 2H) 8 3.8 ppm (triplet, 2H) CH 8 2.9 ppm (singlet, 4H) (f) C,H,CI-, (d) C6H12, (e) C4HoCl4: 8 3.9 ppm (doublet, 4H) δ 4.6 ppm (triplet, 2H) δ 7.1 ppm (broad singlet, 10H)
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a A 5proton signal at 71 ppm indicates a monosubstituted aromatic ring With an index of hydrogen deficiency of 4 C 8 H 10 contains this monosubstitute...View the full answer
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