Ethanol (C2H5OH) burns in air: C2H5OH(l) + O2(g) CO2(g) + H2O(l) Balance the equation and determine
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C2H5OH(l) + O2(g) → CO2(g) + H2O(l)
Balance the equation and determine the volume of air in liters at 35.0°C and 790 mmHg required to burn 227 g of ethanol. Assume that air is 21.0 percent O2 by volume.
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The balanced equation is C 2 H 5 O110 3O 2 0 2CO 2 8 3H ...View the full answer
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