Question: Explain why the following bromoketone forms different bicyclic compounds under different reaction conditions: OCH 0 25 C CH3O CH3OH CH LDA THF
.png)
OCH 0 25 C CH3O CH3OH CH LDA THF
Step by Step Solution
3.50 Rating (163 Votes )
There are 3 Steps involved in it
At low temperatures 78 the proton will be more apt to be removed from the met... View full answer
Get step-by-step solutions from verified subject matter experts
Document Format (1 attachment)
948-C-O-C-R-O-A (1904).docx
120 KBs Word File
